The addition of HCl to an alkene proceeds in two steps. The first step is the attack of H+ ion to> C= C< portion which can be shown as

(iv) All these are possible

Answers (1)

The answer is the option (ii) because the double bond is an electron source. The charge flows from higher electron density; thus, the proton is attacked by n electrons of the double bond.

It can be shown as

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