The correct IUPAC name of the following alkane is

(i) 3,6 – Diethyl – 2 – methyloctane
(ii) 5 – Isopropyl – 3 – ethyloctane
(iii) 3 – Ethyl – 5 – isopropyloctane
(iv) 3 – Isopropyl – 6 – ethyloctane

 

Answers (1)

The answer is the option (i) 3,6-Diethyl-2-methyloctane

Explanation: Since the alkane has 8 carbon atoms, it is octane, viz., the longest chain. There is a methyl group on carbon 2, ethyl groups on carbon 3 & 6. Since 2 ethyl groups are present, it will be diethyl, and alphabetically it comes before methyl. The lowest sum rule is followed by side chains present on the carbon atoms 2, 3 & 6. Hence, the option (i).

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