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What will be the molality of the solution containing 18.25 g of HCI gas in 500 g of water?

(i) 0.1 m

(ii) 1M

(iii) 0.5 m

(iv) 1m

Answers (1)

The answer is the option (iv) 1m


Number. of moles of HCl =\frac{18.25}{36.5}=0.5

Molality (m) = Number of moles (in the solute)/ Mass of the solute (kg)

Molality =\frac{0.5\times 1000}{500}

Molality = 1m

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