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  • What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL? (i) 4 mol L^ -1 (ii) 20 mol L^ -1 (iii) 0.2 mol L ^-1(iv) 2 mol L ^-1

What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?

(i) 4 mol L-1

(ii) 20 mol L-1

(iii) 0.2 mol L-1

(iv) 2 mol L-1

Answers (1)

The answer is the option (iii) 0.2 mol L-1

Explanation: First, calculating the number of moles of NaCl =\frac{5.85}{58.5}=0.1\; mol/L

500\; ml=\frac{500}{1000}=0.5L

Molarity (M) = number of moles of solute/ Volume of solution in litres

Molarity  =\frac{0.1}{0.5}

Molarity = 0.2 M

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