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Need solution for RD Sharma Class 12 Chapter Functions Exercise 2.3 Question 4 Sub question (iii) maths textbook solution.

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Answer : f \circ f(x)=4 x+15

Given : Here given that f(x)=2 x+5 \text { and } g(x)=x^{2}+1

Here we have to compute f\; o\; f

Solution :

              Since f(x) and g(x) are polynomials

\Rightarrow \quad f: R \rightarrow R \text { and } g: R \rightarrow R

\begin{aligned} \Rightarrow \quad f \circ f(x) &=f(f(x)) \\ &=f(2 x+5) \\ &=2(2 x+5)+5 \\ &=4 x+10+5 \\ &=4 x+15 \end{aligned}

Hence, f \circ f(x)=4 x+15

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