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Explain solution RD Sharma class 12 chapter Functions exercise 2.1 question 10  maths

Answers (1)

Given A= \left \{ 1,2,3 \right \}

Number of element in A =3

We know that,

Number of one-one functionnumber of ways of arranging 3 elements.

   =3! = 6

Hence, the number of one-one function as following:

\\(i) \{(1,1),(2,2),(3,3)\}\\ (ii) \{(1,1),(2,3),(3,2)\}\\ (iii) \{(1,2),(2,1),(3,3)\}\\ (iv) \{(1,2),(2,3),(3,1)\}\\ (v) \{(1,3),(2,2),(3,1)\}\\ (vi) \{(1,3),(2,1),(3,2)\}\\

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