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80 bulbs are selected at random from a lot and their life time (in hrs) is recorded in the form of a frequency table given below :

Life time (in hours) 300 500 700 900 1100
Frequency 10 12 23 25 10

One bulb is selected at random from the lot. The probability that its life is 1150 hours, is

 (A)\ \frac{1}{80}

 (B)\ \frac{7}{16}

 (c)\ 0

 (D)\ 1

Answers (1)

Answer : C

\text {P}=\frac{\text {favourable outcome}}{\text {Total outcomes}}

Bulb’s life is given as 1150 hours.

From the table, we can see that no bulb has life as1150 hours.

So favourable outcomes =0

Required probability =\frac{0}{10+12+23+25+10}=0

Therefore option (C) is correct.

Posted by

infoexpert23

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