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A recent survey found that the ages of workers in a factory is distributed as follows:

Age (in years) 20-29 30-39 40-49 50-59 60 and above
Number of workers 38 27 86 46 3

If a person is selected at random, find the probability that the person is:

(i) 40 years or more

(ii) under 40 years

(iii) having age from 30 to 39 years

(iv) under 60 but over 39 years

Answers (1)

 \text{Probability}=\frac{\text {Favourable outcomes}}{\text {Total number of events}}

Here, total events = total number of workers= 38 + 27 + 86 + 46 + 3 = 200

(i) p (person is 40 years or more) = p(person having age 40 to 49 years) + p (person having age 50 to 59 years) + p (having age 60 and above)

=\frac{86}{200}+\frac{46}{200}+\frac{3}{200}=\frac{135}{200}=0.675

(ii) p(person is under 40 years) = p(person having age 20 to 29 years) + p(person having age 30 to 39 years)

=\frac{38}{200}+\frac{27}{200}=\frac{65}{200}=0.325

Hence the different age group decided the work.

\text{(iii) p(having age from 30 to 39 years) }=\frac{27}{200}=0.135

(iv) p(under 60 but over 39 years) = p(person having age 40 to 49 years) + p (person having age 50 to 59 years)

=\frac{86}{200}+\frac{46}{200}=\frac{132}{200}=0.66

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