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A school has five houses A, B, C, D and E. A class has 23 students, 4 from house A, 8 from house B, 5 from house C, 2 from house D and rest from house E. Asingle student is selected at random to be the class monitor. The probability that theselected student is not from A, B and C is
(A) \frac{4}{23}                 (B) \frac{6}{23}                   (C) \frac{8}{23}                   (D) \frac{17}{23}

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Answer.     [B]
Solution.  Probability: probability means possibility. It is a branch of mathematics that deals with the occurrence of a
random event. The value is expressed from zero to one.
Total students = 23
Students in A, B, C = 4 + 8 + 5 = 17
Students in C, D = 23 – 17 = 6
Number of favourable cases = 6
Let A be the event that the student is not from A, B, C

p\left ( A \right )= \frac{Student\, from\, C,D}{Total\, students}

p\left ( A \right )= \frac{6}{23}

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