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One ticket is drawn at random from a bag containing tickets numbered 1 to 40. The probability that the selected ticket has a number which is a multiple of 5 is

(A) \frac{1}{5}                     (B) \frac{3}{5}                     (C) \frac{4}{5}                     (D) \frac{1}{3}

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Answer.   [A]
Solution.  Probability: probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.
Total tickets = 40
Number of tickets multiple of 5 = 5, 10, 15, 20, 25, 30, 35, 40
Total favourable cases = 8
Let A be the event of getting a ticket with number multiple of 5.
p(A) = \frac{Number\, of\, tickets\, the\, bought}{Total\, tickets}
p\left ( A \right )= \frac{8}{40}= \frac{1}{5}

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