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A student says that if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and
the probability of getting ‘not 1’ each is equal to \frac{1}{2} . Isthis correct? Give reasons.

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Answer.    [False]
Solution.  Probability: probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.
Here total cases = 6
Number of favourable cases in getting 1 = 1
Probability = \frac{Number\, of\, favourable\ cases, }{Total\, number\, of\, cases} 
Probability of getting 1= \frac{1}{6}
Number of favourable cases 'not 1' = 5      (2, 3, 4, 5, 6)
Probability of not 1 = \frac{5}{6}
Hence they are not equal to \frac{1}{2}

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