#### All the vertices of a rhombus lie on a circle. Find the area of the rhombus, if area of the circle is 1256 cm2. (Use $\pi$ = 3.14).

Solution

Given that area of circle =1256cm2
$\\\pi r^{2}=1256\\\\ r^{2}=\frac{1256}{314}\times 100\\\\ r^{2}=400 \; \; \; \; \; \; \; \; \left ( \pi=3.14 \right )\\\\ r=\sqrt{400}\\\\ r=20cm$

Diameter of circle = 40 cm

As we know that the diameter of circle is equal

Diagonals of rhombus = Diameters of circle = 40 cm

Each diagonals of rhombus = 40 cm

Area of rhombus =$\frac{1}{2}$  $\times$ product of digonals

= $\frac{1}{2}$  $\times$ 40 $\times$ 40

= 800cm2

Hence required area of rhombus is =800cm2