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  • Find the area of the shaded region in Figure.

Find the area of the shaded region in Figure.

Answers (1)

235.44 m2

Solution

 

There are two semi-circle with diameter (d) 4 cm.

Radius(r) =\frac{d}{2}=\frac{4}{2}=2m

Area of semi-circle =\frac{1}{2}\times \pi \times (r)^{2}=\frac{1}{2}\times \pi \times (2)^{2}=2 \pi

Length and breadth of rectangle ABCD is 16m and 4m respectively

Area of ABCD=16 x 4=64 m2                        (\because Area of rectangle = length× breadth)

Length and breadth of rectangle UVWX is 26m and 12m respectively

Area of UVWX=26 x 12 =312 m2                 (\because Area of rectangle = length× breadth)

Area of shaded region = Area of UVWX – Area of ABCD – 2 × Area of semi-circle

                                   \\=312 -64-2(2 \pi)\;\;\;\;\;\;\;\;\;\;(here \; \pi=3.14)\\ =312-64-12.56\\ =235.44 m^{2}

                                                

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