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#### Balance the following equations by the oxidation number method.

2+                                    6+    2-               +3     +3

(a) Balance the inceases and decreases in O.N.

2+                                    6+    2-               +3     +3

(b) Balancing H and O atoms by adding  molecules

O.N. increases by +5

Now, we know that the total increase in O.N. = and the reduction in O.N. = 1
In order to equalize O.N., we will multiply with 10, which will give us,

Now, we will be balancing the atoms other than O and H, to give us

Now, on balancing O and H we will get,

0        +2                   -1           +2.5

Total increase in O.N.

Total decrease in O.N.

To equalise O.N. multiply  and by 2.

+4                +3                    +2            +4

Total increase in O.N.

Total decrease in O.N.

Now, in order to equalize O.N., we will multiply  with 2 to give us,

Now, we will balance H and O by adding 2H2O on the right side, and 4H+ on the left side of equation.