A bag contains 10 red, 5 blue and 7 green balls. A ball is drawn at random. Find the probability of this ball being a

(i) red ball
(ii) green ball
(iii) not a blue ball

Answers (1)

(i) Answer. [5/11]
Solution. Probability; Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one
Total balls = 10 + 5 + 7 = 22
Red balls = 10
Probability = \frac{Number\, of\, favourable\ cases }{Total\, number\, of\, cases}
Probability of getting red ball = \frac{10}{22}= \frac{5}{11}

(ii) Answer.  [7/22]
Solution.   Probability; Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one

Total balls = 10 + 5 + 7 = 22
Green balls = 7
Probability = \frac{Number\, of\, favourable\ cases }{Total\, number\, of\, cases}
Probability of getting green ball = \frac{7}{22}

(iii) Answer. [17/22]
Solution. Probability; Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one
Total balls = 10 + 5 + 7 = 22
Not a blue ball = 22  – (blue ball)
= 22 – 5 = 17
robability = \frac{Number\, of\, favourable\ cases }{Total\, number\, of\, cases}
Probability of getting not a blue ball = \frac{17}{22}

 

 

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