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If the length of an arc of a circle of radius r is equal to that of an arc of a circle of radius 2r, then the angle of the corresponding sector of the first circle is double the angle of the corresponding sector of the other circle. Is this statement false? Why?

Answers (1)

True

Solution

\because  Formula of length of arc= \frac{2 \pi r\theta }{360}

Let Radius of first circle = r

Length of arc =\frac{2 \pi r\theta_{1} }{360}                         ….. (1)                                                 {\theta _{1} is the angle of first circle}

Radius of second circle = 2r

Length of arc= \frac{2 \pi (2r)\theta_{2} }{360}

                   =\frac{4\pi r\theta_{2} }{360}                       …..(2) {\theta _{2}  is the angle of second circle}

According to question

\\\frac{2 \pi r\theta_{1} }{360}=\frac{4\pi r\theta_{2} }{360}\\\\ \theta_{1} =2\theta_{2}

No, this statement is True

 

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