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In a medical examination of students of a class, the following blood groups are recorded:

Blood Group A AB B O
Number of students 10 13 12 5

A student is selected at random from the class. The probability that he/she has blood group B, is:

 (A)\ \frac{1}{4}

 (B)\ \frac{13}{40}

(C)\ \frac{3}{10}

(D)\ \frac{1}{8}

Answers (1)

Answer : B

\text {P}=\frac{\text {favourable outcomes}}{\text {Total possible outcome}}

Number of students with blood group B =12

Total number of students =10+13+12+5

Required probability

=\frac{12}{10+13+12+5}=\frac{12}{40}=\frac{3}{10}

Therefore option (B) is correct.

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