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  • In triangle ABC, AB = AC and angle B = 50^{\circ}. Then angle C is equal to (A) 40^{\circ} (B) 50^{\circ} (C) 80^{\circ} (D) 130^{\circ}

In $\triangle A B C, \mathrm{AB}=\mathrm{AC}$ and $\angle B=50^{\circ}$. Then $\angle C$ is equal to
(A) $40^{\circ}$
(B) $50^{\circ}$
(C) $80^{\circ}$
(D) $130^{\circ}$

Answers (1)

Solution.        

We know that angles opposite to equal sides of a triangle are equal

$ AB = AC$

 

Since $\angle B$ is opposite to side $A C$ and $\angle C$ is opposite to side $A B$

$
\therefore \angle B=\angle C=50^{\circ}\left(\because \angle B=50^{\circ} \text { given }\right)
$

Hence option (B) is correct.

Posted by

infoexpert24

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