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  • The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is (A) (0, 0) (B) (0, 2) (C) (2, 0) (D) (–2, 0)

The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is

(A) (0, 0)

(B) (0, 2)

(C) (2, 0)

(D) (–2, 0)

Answers (1)

The point which lies on the perpendicular bisector is the co-ordinate of mid-point on the line joining the points A(–2, –5), B(2, 5).

Let this point is (x, y)

\\ \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(-2,-5) \quad\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)=(2,5) \\ (\mathrm{x}, \mathrm{y})=\left(\frac{\mathrm{x}_{1}+\mathrm{x}_{2}}{2}, \frac{\mathrm{y}_{1}+\mathrm{y}_{2}}{2}\right) \\ (\mathrm{x}, \mathrm{y})=\left(\frac{-2+2}{2}, \frac{-5+5}{2}\right) \\ (\mathrm{x}, \mathrm{y})=(0,0)

Hence, the required point is (0, 0)

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infoexpert21

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