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Three incandescent bulbs of 100 W each are connected in series in an electric circuit. In another circuit another set of three bulbs of the same wattage are connected in parallel to the same source. 

(a) Will the bulb in the two circuits glow with the same brightness? Justify your answer. 

(b) Now let one bulb in both the circuits get fused. Will the rest of the bulbs continue to glow in each circuit? Give reason. 

Answers (1)

(a) Let, resistance of each bulb is R

Case (1): connected in series

Net resistance = R + R + R = 3R

Current in each bulb = V/3R

 

Case (2): connected in parallel

1/Net resistance = 1/R + 1/R + 1/R = 3/R

Net resistance = R/3

Net Current = 3V/R

In parallel, current will be equally divided among all the bulbs.

Current in each bulb = V/R

As current is more in case (2), bulbs will glow brighter

Blubs will glow brighter in parallel combination.

 

(b) If one bulb is fused, in series, all bulbs will not glow as the circuit gets broken and current stops flowing.

In parallel combination, other bulbs will glow as short circuiting of one bulb will not affect the voltage of other bulbs.

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