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  • A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16  seconds would be roughly  (a) 10^{20} (b) 10^{16} (c) 10^{18}

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in 16 
seconds would be roughly 
(a) 1020
(b) 1016
(c) 1018
(d) 1023 

Answers (1)

Answer: (a)

Solution:

Given Current:
I = 1A
Time (t) = 16s
I=\frac{Q}{t}=\frac{ne}{t}
n=\frac{It}{e}

Where e = charge of electron = 1.6\times 10^{-19}C
n=\frac{1\times 16}{1.6\times 10^{-19}}=10^{20}

Therefore, option (a) is correct.

Posted by

infoexpert26

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