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A cylindrical conductor of length l and uniform area of cross section A has resistance R. Another conductor of length 2l and resistance R of the same material has area of cross section 
(a) A/2 
(b) 3A/2 
(c) 2A 
(d) 3A 

Answers (1)

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Answer: (c)

Solution:
The resistivity of 1st conductor
p=\frac{RA}{l}
Resistivity of 2nd conductor should be the same as they are made of same material
Let area of 2nd conductor = A1 

p=\frac{RA_{1}}{2l}
Now,
p=\frac{RA}{l}=\frac{RA_{1}}{2l}
Which gives,
A1 =2A

Therefore, option (c) is correct.
 

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