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Two coins are tossed 1000 times and the outcomes are recorded as below :

Number of heads 2 1 0

Frequency 200 550 250

Based on this information, the probability for at most one head is:

$(A)\ \frac{1}{5}$

$(B)\ \frac{1}{4}$

$(C)\ \frac{4}{5}$

$(D)\ \frac{3}{4}$

Answers (1)

Answer : C

Total number of outcomes =200+550+250=1000

At most one head = 0head+ 1 head

Number of favourable outcomes =250+550=800

Probability will be

$=\frac{800}{1000}=\frac{4}{5}$

Therefore option (C) is correct.

Posted by

infoexpert23

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