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Please Solve R.D.Sharma class 12 Chapter 25 Scalar Triple Product  Exercise 25.1 Question 3 Sub Question 2 Maths textbook Solution.

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Answer :- 35 cubic units

Hint :- Use formula of parallelepiped =\left [ \vec{a}\: \: \: \vec{b}\: \: \: \vec{c} \right ]

Given:-\begin{aligned} &-\vec{a}=2 \hat{\imath}-3 \hat{\jmath}+4 \hat{k} \\ \end{aligned}

\begin{aligned} &\vec{b}=\hat{i}+2 \hat{\jmath}-\hat{k} \\ &\vec{c}=3 \hat{\imath}-\hat{\jmath}-2 \hat{k} \\ \end{aligned}

Volume of parallelepiped,=\left [ \vec{a}\: \: \: \vec{b}\: \: \: \vec{c} \right ]

\begin{aligned} &=\left|\begin{array}{ccc} 2 & -3 & 4 \\ 1 & 2 & -1 \\ 3 & -1 & -2 \end{array}\right| \\ \end{aligned}

\begin{aligned} &=2(-4-1)+3(-2+3)+4(-1-6) \\ &=2(-5)+3(1)+4(-7) \\ &=-10+3-28 \\ &=-35 \\ &=35 \text { cubic units } \end{aligned}

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