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Please Solve R.D.Sharma class 12 Chapter 25 Scalar Triple Product  Exercise 25.1 Question 3 Sub Question 3 Maths textbook Solution.

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Answer :- 286 cubic units

Hint :- Use formula of volume of parallelepiped

Given:-  \begin{aligned} &\vec{a}=11 \hat{\imath}=11 \hat{\imath}+0 \hat{\jmath}+0 \hat{k} \\ \end{aligned}

\begin{aligned} &\vec{b}=2 \hat{\jmath}=0 \hat{\imath}+2 \hat{\jmath}+0 \hat{k} \\ &\vec{c}=13 \hat{k}=0 \hat{\imath}+0 \hat{\jmath}+13 \hat{k} \end{aligned}

Volume of parallelepiped, =\left [ \vec{a}\: \: \vec{b}\: \: \vec{c} \right ]

\begin{aligned} &=\left|\begin{array}{ccc} 11 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 13 \end{array}\right| \\ &=11(26-0)-0(0-0)+0(0-0) \\ &=286 \text { cubic units } \end{aligned}

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