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Need solution for RD Sharma maths Class 12 Chapter 29 Linear Programming Exercise Multiple Choice Question Question 14 textbook solution.

Answers (1)

Answer: (c) bounded in first quadrant

Hint:

Convert the inequalities into equation

Given:

x, y \geq 0, y \leq 6, x+y \leq 3

Solution :

Let’s convert the given inequalities into equations, we obtain

y=6, x+y=3, x=0, y=0

y=6 is the line passing through (0,6)and parallel to the x-axis. The region below the line y=6 will satisfy the given inequalities.

The line x+y=3 meets the coordinate axis at A (3,0) and B (0,3). Join these point to obtain the line x+y=3 . Clearly  (0,0)satisfies the inequalities x+y\leq 3. So, the region in xy-plane that contains the origin represents the solution set of the given equation.

Region represented by x\geq 0 and y\geq 0

Since, every point in the first quadrant satisfies these inequalities. So, the first quadrant is the region represented by the inequalities.

So, the correct option is (c)

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