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 A cylindrical conductor of length l and uniform area of cross section A has resistance R. Another conductor of length 2l and resistance R of the same material has area of cross section 

(a) A/2 

(b) 3A/2 

(c) 2A 

(d) 3A 

Answers (1)

Answer: (c)

Solution:

The resistivity of 1st conductor

p=\frac{RA_{1}}{l}

Resistivity of 2nd conductor should be the same as they are made of same material

Let area of 2nd conductor = A1

                        p=\frac{RA_{1}}{2l}

Now,

p=\frac{RA}{l}=\frac{RA_{1}}{2l}

Which gives,

A1=2A

Therefore, option (c) is correct.

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