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An element is placed in 2nd Group and 3rd Period of the Periodic Table, burns in presence of oxygen to form a basic oxide.
(a) Identify the element
(b) Write the electronic configuration
(c) Write the balanced equation when it burns in the presence of air
(d) Write a balanced equation when this oxide is dissolved in water
(e) Draw the electron dot structure for the formation of this oxide

Answers (1)

a) Element is in 2nd Group and 3rd Period that means it belongs to Alkali Earth Metals and it is Magnesium (Mg).

b) Atomic Number of Magnesium is 12 whose electronic configuration is:
K     L     M

2      8     2
c) When Magnesium is burnt in the presence in air it will form Magnesium Oxide. 
2Mg\left ( s \right )+O_{2}\left ( g \right )\overset{Heat}{\rightarrow}2MgO\left ( s \right )
d) When Magnesium Oxide is dissolved in water it will form Magnesium Hydroxide.
2MgO\left ( s \right )+2H_{2}O\left ( l \right )\rightarrow 2Mg\left ( OH \right )_{2}
e) Electronic Configuration of Magnesium:  2      8          2
Electronic Configuration of Oxygen:            2       6

Electron Dot Structure:


 

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