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Equations of diagonals of the square formed by the lines x = 0, y = 0, x = 1 and y = 1 are
A. y = x, y + x = 1
B. y = x, x + y = 2
C. 2y = x, y + x = 1/3
D. y = 2x, y + 2x = 1

Answers (1)

It is given that the lines x=0, y=0 , x=1 and y=1 form a square of side 1 unit 

Let us form a square OABC having corners O(0,0) from the given lines 

with A(1,0), B(1,1) and C(0,1)

    Now we have to find the equation of the diagonal AC  

   Equation of a line is found out by y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\left ( x-x_{1} \right )

   y-0=\frac{1-0}{0-1}\left ( x-1 \right )

   y=-1(x-1)  

 y=-x+1  

  x+y=1 

   Equation of diagonal OB is y-0=\frac{1-0}{1-0}\left ( x-0 \right )

  y=x 

 y=x  

Hence, the correct option is (a)

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