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The points (3, 4) and (2, – 6) are situated on the ____ of the line 3x – 4y – 8 = 0.

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Given line 3x-4y-8=0 and given points are  (3,4) and (2,-6) 

  For point (3,4) 

  3(3)-4(4)-8=9-16-8 

 =9-24= -15<0 

For point (2, -6)     

3(2)-4(-6)-8  =6+24-8 

=30-8=22>0  

So, the points (3,4) and (2,-6) are situated on the opposite sides of 3x-4y-8=0

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