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  • The distance between the lines y equal to mx plus c1 and y equal to mx plus c2 is A c1 minus c2 divided square root of m square plus 1 B determinant of c1 minus c2 divided 1 plus square root of m square C c2 minus c1 divided 1 plus square root of m D 0

The distance between the lines y = mx + c1 and y = mx + c2 is
A. \frac{c_{1}-c_{2}}{\sqrt{m^{2}+1}}


B. \frac{\left |c_{1}-c_{2} \right |}{\sqrt{1+m^{2}}}


C. \frac{c_{2}-c_{1} }{\sqrt{1+m^{2}}}


D. 0

Answers (1)

Given equations are y=mx+c1….(i)   and y=mx+c2…….(ii)   

Firstly, we find the slope of both the equations 

  Since, both of them have the same slope  they are parallel lines.  

  We know that distance between two parallel  lines Ax+By+C1=0 and Ax+By+C2=0 

  d=\frac{\left | c_{1}-c_{2} \right |}{\sqrt{A^{2}+B^{2}}}=\frac{\left | c_{1}-c_{2} \right |}{\sqrt{m^{2}+\left ( -1 \right )^{2}}}=\frac{\left | c_{1}-c_{2} \right |}{\sqrt{m^{2}+1}}

Hence, the correct option is b

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infoexpert22

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