A line cutting off intercept – 3 from the y-axis and the tangent at angle to the x-axis is 3/5, its equation is
A. 5y – 3x + 15 = 0
B. 3y – 5x + 15 = 0
C. 5y – 3x – 15 = 0
D. None of these
. Given that tanθ=3/5
We know that slope of a line, m=tanθ Slope of line, m=3/5
Since, the lines cut off intercepts -3 on y axis so the line is passing
through the point (0,-3)
So, the equation of line is y-y1=m(x-x1)
y-(-3)=3/5(x-0)
y+3=3x/5
5y+15=3x
5y-3x+15=0
Hence, the correct option is (a)