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 A line cutting off intercept – 3 from the y-axis and the tangent at angle to the x-axis is 3/5, its equation is
A. 5y – 3x + 15 = 0

B. 3y – 5x + 15 = 0
C. 5y – 3x – 15 = 0
D. None of these

Answers (1)

. Given that tanθ=3/5 

 We know that slope of a line, m=tanθ  Slope of line, m=3/5  

 Since, the lines cut off intercepts -3 on y axis so the line is passing 

through the point (0,-3) 

 So, the equation of line is y-y1=m(x-x1

 y-(-3)=3/5(x-0) 

 y+3=3x/5

  5y+15=3x  

 5y-3x+15=0

 Hence, the correct option is (a)

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