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Find the equation of the line passing through the point (5, 2) and perpendicular to the line joining the points (2, 3) and (3, – 1).

Answers (1)

 Given points are A(5,2) B(2,3) and C(3,-1).

  Slopeof the line joining points B and C = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{-1-3}{3-2}=-\frac{4}{1}=-4

It is given that line passing through the point A is perpendicular to BC 

   m1*m2= -1 

-4*m2=-1  

m2=1/4 

 Equation of line passing through point A  

  Equation of line: y-y= m(x-x1)   

 y-2=1/4 (x-5)  

 4y-8=x-5  

 x-5-4y+8=0   

  Equation of straight line passing through point A is x-4y+3=0  

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