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  • Find out the following in the electric circuit given in Figure 12.9 (a) Effective resistance of two 8 omega resistors in the combination (b) Current flowing through 4 omega resistor (c) Potential difference across 4 omega resistance

Find out the following in the electric circuit given in Figure 12.9

(a) Effective resistance of two 8 Ω resistors in the combination 

(b) Current flowing through 4 Ω resistor 

(c) Potential difference across 4 Ω resistance 

(d) Power dissipated in 4 Ω resistor 

(e) Difference in ammeter readings, if any. 

Answers (1)

Explanation:-

(a) Parallel combination of two 8-ohm resistors

Equivalent resistor in parallel combination:
\frac{1}{R_{eq}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}+\frac{1}{R_{4}}...................\\ \frac{1}{R_{eq}}=\frac{1}{8}+\frac{1}{8}=\frac{2}{8}\\ \frac{1}{R_{eq}}=\frac{1}{4}\\ R_{eq}=4 \Omega                                                                                                                                                                                   

(b) Total resistance in the circuit is: 4 \Omega + 4 \Omega = 8 \Omega

Given voltage in the circuit = 8 V

Current through the circuit: I = \frac{V}{R}=\frac{8}{8}=1A

(c) Potential difference across 4 \Omega = IR = (4 × 1) V = 4V

(d) Energy dissipated in 4 \Omega is I2R = 12 × 4 = 4W

(e) No, there is no difference in ammeter A1 and A2 reading as the same current passes through the ammeter.

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