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  • Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. Suggest how can he identify the produced gas.

Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. Suggest how can he identify the produced gas. Write chemical equations for both the reactions.

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Ans.
M is lustrous, so the element has to be a metal.
As it reacts with NaOH, it should be a very reactive metal.
Metal + Base \rightarrow Hydrogen gas
Also the metal reacts with HCl
Metal + acid \rightarrow salt + hydrogen
The divalent element M is Zn
Zn\left ( s \right )+2NaOH\left ( aq \right )\rightarrow Na_{2}ZnO_{2}\left ( aq \right )+H_{2}
Zn\left ( s \right )+2HCl\left ( aq \right )\rightarrow ZnCl_{2}\left ( aq \right )+H_{2}
The produced gas can be identified by bringing a burning match stick near the gas. The gas burns with a pop sound, hence it is hydrogen.

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