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Give the steps involved in the extraction of metals of low and medium reactivity from their respective sulphide ores.

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Extraction of metals of low and medium reactivity:
1.Roasting: a respective sulphide ore is heated in air. So, metal oxide is formed.
2.Heating of metal oxide to obtain the metal
Mercury has low reactivity.
We can see the entire process for mercury (Hg) as follows:
(i) Roasting: Metal sulphide is converted into metal oxide by heating the ore strongly in the presence of excess of air.
2HgS+3O_{2}\rightarrow 2HgO+2SO_{2} (Metal oxide is formed)
(ii) Reduction: Metal oxide is then reduced to metal by heating it.
2HgO\rightarrow 2Hg+O_{2}
Hence mercury is extracted.
Similarly, we can see for zinc (medium reactivity).
Roasting: 2ZnS+3O_{2}\rightarrow 2ZnO+2SO_{2}

Reduction:ZnO+C\rightarrow Zn+CO

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