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The annual rainfall record of a city for 66 days is given in the following table.

Rainfall (in cm) 0-10 10-20 20-30 30-40 40-50 50-60

Number of days 22 10 8 15 5 6

Calculate the median rainfall using ogives (of more than type and of less than type)

Answers (1)

Answer. [20]
Solution.

(i) less than type		(ii) more than type
Rainfall	No.of days	Rainfall	Number of days
less than 0	0	more than or equal to 0	66
less than 10	0+22 = 22	more than or equal to 10	66-22 = 44
less than 20	22+10 = 32	more than or equal to 20	44-10 = 34
less than 30	32+8 = 40	more than or equal to 30	34-8 = 26
less than 40	40+15 = 55	more than or equal to 40	26-15 = 11
less than 50	55+5 =60	more than or equal to 50	11 - 5 =6
less than 60	60+6 =66	more than or equal to 60	6-6 =0

Now let us draw ogives of more than type and of less than type then find the median

$N= 66,\frac{N}{2}= \frac{66}{2}= 33$

Here median is 20

Posted by

infoexpert27

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