Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 Chapter 8 Continuity exercise 8.1 question 19

Explain solution RD Sharma class 12 Chapter 8 Continuity exercise 8.1 question 19

Answers (1)

Answer:

                k=-1 

Hint:

For a function to be continuous at a point, its LHL RHL and value at that point should be equal.

Solution:

Given,  

                f(x)=\left(\begin{array}{c} \frac{x^{2}-3 x+2}{x-1}, \text { if } x \neq 1 \\\\ k, \text { if } x=1 \end{array}\right)

If f\left ( x \right )  is continuous at x=1 , then

                \begin{aligned} &\lim _{x \rightarrow 1} f(x)=f(1) \\\\ &\lim _{x \rightarrow 1} \frac{x^{2}-3 x+2}{x-1}=k \end{aligned}

                \begin{aligned} &\lim _{x \rightarrow 1} \frac{(x-2)(x-1)}{x-1}=k \\\\ &\lim _{x \rightarrow 1}(x-2)=k \\\\ &k=-1 \end{aligned}

               

               

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE opens portal for uploading internal grades for Class 12 board practical exams 2025
anam-khan

Record 3.25 crore students register for PM Modi's Pariksha Pe Charcha 2025
anam-khan

Over 3 crore students register for PM Modi’s Pariksha Pe Charcha 2025

Latest Question