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  • Please solve RD Sharma class 12 chapter Continuity exercise 8.2 question 4 subquestion (ii) maths textbook solution

Please solve RD Sharma class 12 chapter Continuity exercise 8.2 question 4 subquestion (ii) maths textbook solution

Answers (1)

Answer:

 k = -2

Hint:

 Put LHL = RHL = f(2)

Given:

 f(x)= \begin{cases}k x+5 & x \leq 0 \\ x-1 & x>0\end{cases}

Explanation:

LHL = RHL = f(2)                 ....(1)

\begin{aligned} &\text { L.H.L } =\lim _{x \rightarrow 2^{-}} f(x)=\lim _{h \rightarrow 0}(2-h)=\lim _{h \rightarrow 0} k(2-h)+5 \\ &=2 k+5 \end{aligned}

R . H . L=\lim _{x \rightarrow 2^{+}} f(x)=\lim _{h \rightarrow 0}(2+h)=\lim _{h \rightarrow 0} k(2+h)-1=1

Using (1) we get

\begin{aligned} &\therefore 2 k+5=1 \\ &2 k=1-5 \\ &=-4 \\ &k=-2 \end{aligned}

Posted by

Gurleen Kaur

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