Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths class 12 chapter 8 Continuity exercise multiple choice question 11

Need solution for RD Sharma maths class 12 chapter 8 Continuity exercise multiple choice question 11

Answers (1)

Answer:

 The correct option is (b)

Hint:

 Use the given formula:

 \begin{aligned} &\text { (i) } \lim _{x \rightarrow 0} f(x) g(x)=e \lim _{x \rightarrow 0}(f(x)-1) \cdot g(x)\\ &\text { Where } \lim _{x \rightarrow 0} f(x)=1 \end{aligned}

\begin{aligned} &\text { And } \lim _{x \rightarrow 0} g(x)=0\\ &\text { (ii) } \lim _{x \rightarrow 0}\left\{\frac{\cos x-1}{x}\right\}=-1 \end{aligned}

(iii) A function f(x) is said to be continuous at a point x = a of its domain, if

\lim _{x \rightarrow a^{+}} f(a+h)=\lim _{x \rightarrow a^{-}} f(a-h)=f(a)

Given:

f(x)=\left\{\begin{array}{l} (\cos x)^{\frac{1}{x}} \\ k \end{array}\right.    \begin{aligned} , x & \neq 0 \\ , x &=0 \end{aligned}

And f(x) is continuous at x = 0

Solution:

\lim _{x \rightarrow 0} f(x)=f(0)

Calculate the value of k

\lim _{x \rightarrow 0}(\cos x)^{\frac{1}{x}}=k

Using formula (i)

\lim _{x \rightarrow 0} f(x)^{g(x)}=e \lim _{x \rightarrow 0}\left\{\frac{\cos x-1}{x}\right\}=k

Apply formula (ii)

\begin{aligned} &e^{0}=k \\ & k=1 \end{aligned}

So, option (b) is correct.

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question