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Please solve RD Sharma class 12 chapter 12 Derivative as a Rate Measurer exercise multiple choise question 13 maths textbook solution

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A. \: \: 9


We are given the distance travelled as a function of time, we can calculate velocity by

\begin{aligned} &V(t)=\frac{d s}{d t} \\ \end{aligned}


\begin{aligned} s=45 t+11 t^{2}+3 \end{aligned}


→ Differentiating (i) with respect to t, we get

\begin{aligned} &V(t)=\frac{d s}{d t} =45 t+11 t^{2}+3 \end{aligned}

→ If the particle is at rest, then it’s velocity will be 0

→ Solving the quadratic equation we get

t=\frac{-5}{3}, \quad t \neq 0 \quad \text { so, } t=9

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Gurleen Kaur

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