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  • Provide solution RD Sharma maths class 12 chapter 12 Derivative as a Rate Measure exercise case study based question, question 1 sub question 4 maths textbook solution

Provide solution RD Sharma maths class 12 chapter 12 Derivative as a Rate Measure exercise case study based question, question 1 sub question 4 maths textbook solution

Answers (1)

Answer:

 -1.6 cm/sec

Hint:

 Here, we use the basic concept of diagonal plate

Given:

 Here x=8cm and y=6cm

Solution:

 x=8cm and y=6cm

According to Pythagoras

P^{2}=x^{2}+y^{2} …….(1)

=64+36

=100

P=10

Differentiate (1) w.r.t t we get

\begin{aligned} &2 \times 10 \frac{d p}{d t}=2 \times 8 \times(-5)+2 \times 6 \times 4 \quad, \text { since } \frac{d x}{d t}=-5 \text { and } \frac{d y}{d t}=4 \\ &\frac{d p}{d t}=-1.6 \mathrm{~cm} / \mathrm{sec} \end{aligned}

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