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  • Provide solution RD Sharma maths class 12 chapter 12 derivative as a Rate Measurer exercise case study base question, question 2 sub question 3

Provide solution RD Sharma maths class 12 chapter 12 derivative as a Rate Measurer exercise case study base question, question 2 sub question 3

Answers (1)

Answer: 

\frac{\sqrt{3}}{5}cm/\sec

Hint:

 Here, we use the formula of diagonal

Given:

\frac{da}{dt}=0.2

Solution:

Weknow diagonal of cube \left ( p \right )=\sqrt{3}a

Differentiate it we get

\begin{aligned} &\frac{d p}{d t}=\sqrt{3} \frac{d a}{d t}=\sqrt{3} \times 0.2=\frac{2 \sqrt{3}}{10} \\ &=\frac{\sqrt{3}}{5} \mathrm{~cm} / \mathrm{sec} \end{aligned}

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