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explain solution RD Sharma class 12 chapter Derivative As a Rate Measure exercise 12.2 question 16 sub question (ii) maths

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Answer: \theta=\frac{\pi}{6}

Hint: Here we use the given condition, \frac{d \theta}{d t}=-2 \frac{d(\cos \theta)}{d t}

Given: Whose rate of increase twice as twice the rate of decrease of its cosine.

Solution: As per the condition

\frac{d \theta}{d t}=-2 \frac{d(\cos \theta)}{d t}

As the rate of increase twice as twice the rate of decrease hence the minus sign,

\begin{aligned} &\frac{d \theta}{d t}=-2 \frac{d(\cos \theta)}{d t} \times \frac{d \theta}{d t} \\\\ &1=-2(-\sin \theta) \end{aligned}

\begin{aligned} &\sin \theta=\frac{1}{2} \\\\ &\theta=\frac{\pi}{6} \end{aligned}

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