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Provide solution for RD Sharma maths class 12 chapter Derivative as a Rate Measure exercise 12.1 question 10

Answers (1)

Answer:

M\! R=Rs66. It indicates the extra money spent when number of employees increase from 5 to 6

Given:

R(x)=3x^{2}+36x+5

Solution:

Here we have,

Total revenue

R(x)=3x^{2}+36x+5

To find marginal revenue M\! R let’s differentiate R(x) with respect to x

\therefore \frac{d}{dx}R(x)=M\! R=6x+36                                \left[\because \frac{d\left(x^{n}\right)}{d x}=n x^{n-1}\right]

To find M\! R

Put x=5 in M\! R

\therefore M\! R=6(5)+36

                        \therefore M\! R=66\; Rs

Here we can write

M\! R=\lim _{h \rightarrow 1} \frac{R(x+h)-R(x)}{h}=66

So, we can say thet in first there were 5 employees but after they become 6 employees.

Note:

Here we have taken

M\! R=\lim _{h \rightarrow 1} \frac{R(x+h)-R(x)}{h}

 N\! ot \; \lim _{h \rightarrow 0}\; because\; h\; represents

Number of employees which will always be integer and greater than zero.

Posted by

Gurleen Kaur

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