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provide solution for rd sharma maths class 12 chapter 12 derivatives as a rate measure exercise  fill in the blanks question 2

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Answer: r

Hint: Here, we use the of surface area S=4\pi r^{2}

Given: \frac{dr}{dt}=2\; cm/s

Solution: \frac{ds}{dt}=8\pi r\frac{dr}{dt}

               \frac{ds}{dt}=8\pi r\; \times 2

               \frac{ds}{dt}=16\pi r\;

Rate of change of surface area \infty radius of sphere.


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