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Explain solution RD Sharma class 12 chapter 12 Derivative as a Rate Measurer exercise multiple choise question 16 maths

Answers (1)

Answer:

B.\; r=\frac{1}{\pi }units

Hint:

The area of circle of radius r is defined by

A(r)=\pi r^{2}

Given:

\frac{d A}{d t}=\frac{2 d r}{d t}

Solution:

We get

2 \pi r \frac{d r}{d t}=\frac{2 d r}{d t}\\ \\ \pi r=1 \\ \\ r=\frac{1}{\pi} unite

Posted by

Gurleen Kaur

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