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Please solve rd sharma class 12 chapter 12 derivatives as a rate measure exercise fill in the blanks question 5 maths textbook solution

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Answer: \theta =\frac{\pi }{3}

Hint: Here, we use the concept of \theta angle

Given: Let \theta ,\frac{d\theta }{dt}=\frac{d\left ( \sin \theta \right )}{dt}

Solution: Let \theta increase twice as fast as it’s sine

                \frac{d\theta }{dt}=\frac{2d\left ( \sin \theta \right )}{dt}

                \frac{d\theta }{dt}=2\cos \theta \frac{d\theta }{dt}

                1=2\cos \theta

                \cos \theta = \frac{1}{2}

                \theta = \frac{\pi }{3}


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