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Need solution for RD Sharma maths class 12 chapter 12 Derivative as a Rate Measurer exercise multiple choise question 15

Answers (1)

Answer:

\begin{aligned} &\text { D. } \quad r=\frac{1}{2 \sqrt{n}} \end{aligned}

Hint:

The volume of sphere of radius r is defined by

V(r)=\frac{4}{3}\pi r^{3}

Given:

\frac{dV}{dt}=\frac{dr}{dt}

Solution:

\begin{aligned} &4 \pi r^{2} \times \frac{d r^{\prime}}{d t}=\frac{d r^{\prime}}{d t} \\ &4 \pi r^{2}=1 \end{aligned}

\begin{aligned} &r=\frac{1}{2\sqrt{n}}\: units \end{aligned}

Posted by

Gurleen Kaur

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