Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide Solution for RD Sharma Class 12 Chapter 6 Adjoint and Inverse Matrix Exercise 6.1 Question 6

Provide Solution for RD Sharma Class 12 Chapter 6 Adjoint and Inverse Matrix Exercise 6.1 Question 6

Answers (1)

best_answer

Answer:

\operatorname{Adj}(A)=\left[\begin{array}{ccc} 25 & 0 & 0 \\ 0 & 25 & 0 \\ 0 & 0 & 25 \end{array}\right]

Hint:

Here, we use basic concept of determinant.

Given:

A=\left[\begin{array}{ccc} 1 & -2 & 3 \\ 0 & 2 & -1 \\ -4 & 5 & 2 \end{array}\right]     

Solution:

Let’s find cofactor of A

\begin{aligned} &C_{11}=9, C_{21}=19, C_{31}=-4 \\ &C_{12}=4, C_{22}=14, C_{32}=1 \\ &C_{13}=8, C_{23}=3, C_{33}=2 \end{aligned}

C_{i j}=\left[\begin{array}{ccc} 9 & 4 & 8 \\ 19 & 14 & 3 \\ -4 & 1 & 2 \end{array}\right]

Adj(A)  = Transpose of  C_{ij}

\begin{aligned} &\operatorname{Adj}(A)=\left[\begin{array}{ccc} 9 & 19 & -4 \\ 4 & 14 & 1 \\ 8 & 3 & 2 \end{array}\right] \\ &A \times \operatorname{Adj}(A)=\left[\begin{array}{ccc} 1 & -2 & 3 \\ 0 & 2 & -1 \\ -4 & 5 & 2 \end{array}\right] \times\left[\begin{array}{ccc} 9 & 19 & -4 \\ 4 & 14 & 1 \\ 8 & 3 & 2 \end{array}\right] \end{aligned}

=\left[\begin{array}{ccc} 9-8+24 & 19-28-9 & -4-2+6 \\ 0+8-8 & 0+28-3 & 0+2-2 \\ -36+20+16 & -76+70+6 & 16+5+4 \end{array}\right]=\left[\begin{array}{ccc} 25 & 0 & 0 \\ 0 & 25 & 0 \\ 0 & 0 & 25 \end{array}\right]

Hence, A \times \operatorname{Adj}(A)=25 I        

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE admit card 2025 out for Class 10, 12 supplementary exams
anam-khan

CBSE Class 10, 12 practical exams 2025 for compartment students from July 10; detailed guidelines issued
anam-khan

CBSE Central Sector Scheme of Scholarship 2025 applications open on scholarships.gov.in

Latest Question